每次从字符串开始中心扩散,找到最长的字符串子串
start = i - Math.floor((len-1)/2)是为了适配偶数的情况,偶数的情况中心处于i,i+1之间
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41
|
var longestPalindrome = function (s) { if (!s || s.length < 1) return ""; let start = 0, end = 0; for (let i = 0; i < s.length; i++) { const len1 = expandAroundCenter(s, i, i); const len2 = expandAroundCenter(s, i, i + 1); const len = Math.max(len1, len2); if (len > end - start) {
start = i - Math.floor((len - 1) / 2); end = i + Math.floor(len / 2); } } return s.substring(start, end + 1); function expandAroundCenter(s, left, right) { while (left >= 0 && right < s.length && s[left] === s[right]) { left--; right++; } return right - left - 1; } return result; }; console.log(longestPalindrome("babad"));
|