递增的三元子序列保存两个最小的数,只要找到第三个数就得到了答案 1234567891011121314function increasingTriplet(nums) { let first = Infinity; let second = Infinity; for (const n of nums) { if (n <= first) { first = n; } else if (n <= second) { second = n; } else { return true; } } return false;}